BMIS 330 LAB 18 | Complete Solution
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LAB 18 ANSWER TEMPLATE
Problem 1:
IP address: 192.168.10.0 /27 (given)
a. Subnet Mask: 255.255.255.224
b. Bits Borrowed: 3
c. Number of subnets: 8
d. Magic number: 32
e. Number of valid hosts per subnet: 30
f. (Sub) network address of subnet 0: 192.168.10.0
g. First usable host address in subnet 0: 192.168.10.1
h. Last usable host address in subnet 0: 192.168.10.30
i. Broadcast address in subnet 0: 192.168.10.31
j. (Sub) Network address in subnet 3: 192.168.10.64
k. Last usable host address in subnet 4: 192.168.10.158
Subnet Subnet address 1st Host address Last Host address Broadcast
0 192.168.10.0 192.168.10.1 192.168.10.30 192.168.10.31
1 192.168.10.32 192.168.10.33 192.168.10.62 192.168.10.63
2 192.168.10.64 192.168.10.65 192.168.10.94 192.168.10.95
3 192.168.10.96 192.168.10.97 192.168.10.126 192.168.10.127
4 192.168.10.128 192.168.10.129 192.168.10.158 192.168.10.159
5 192.168.10.160 192.168.10.161 192.168.10.190 192.168.10.191
6 192.168.10.192 192.168.10.193 192.168.10.222 192.168.10.223
7 192.168.10.224 192.168.10.225 192.168.10.254 192.168.10.255
Problem 2:
IP address: 192.168.10.0 / 26 (given)
a. Subnet Mask: ____255.255.255.192_____________________________________
b. Bits Borrowed: ________2_________________________________
c. Number of subnets: _______4__________________________________
d. Magic number: _____________64____________________________
e. Number of valid hosts per subnet: ___62______________________________________
f. (Sub) network address of subnet 0: _____192.168.10.0_____________
g. First usable host address in subnet 0: _____192.168.10.1_____________
h. Last usable host address in subnet 0: ______192.168.10.62
i. Broadcast address in subnet 0: ____________192.168.10.63________________
j. (Sub) Network address in subnet 1: _________192.168.10.64_________________
k. Last usable host address in subnet 2: __________192.168.10.190____________
Subnet Subnet address 1st Host address Last Host address Broadcast
0 192.168.10.0 192.168.10.1 192.168.10.62 192.168.10.63
1 192.168.10.64 192.168.10.65 192.168.10.126 192.168.10.127
2 192.168.10.128 192.168.10.129 192.168.10.190 192.168.10.128
3 192.168.10.192 192.168.10.193 192.168.10.254 192.168.10.255
Etc. 192.168.10.256 192.168.10.257 192.168.10.318 192.168.10.319
Problem 3:
IP address: 192.168.10.0 (given)
Subnet Mask: 255.255.255.240
a. Slash prefix: _____/28____________________________________
b. Bits Borrowed: ___________4_____________________________
c. Number of possible subnets: _____16____________________________________
d. Magic number: ___________16______________________________
e. Number of usable hosts per subnet: _____14____________________________________
f. (Sub) network address of subnet 0: ______192.168.10.0_________________________
g. First usable host address in subnet 0: _____192.168.10.1______________________
h. Last usable host address in subnet 0: ______192.168.10.14__________________
i. Broadcast address in subnet 0: ___________192.168.10.15___________
j. (Sub) Network address in subnet 1: ________192.168.10.16___
k. Last usable host address in subnet 2: _______192.168.10.46___________
Subnet Subnet address 1st Host address Last Host address Broadcast
0 192.168.10.0 192.168.10.1 192.168.10.14 192.168.10.15
1 192.168.10.16 192.168.10.17 192.168.10.30 192.168.10.31
2 192.168.10.32 192.168.10.33 192.168.10.46 192.168.10.47
3 192.168.10.48 192.168.10.49 192.168.10.62 192.168.10.63
Etc. 192.168.10.64 192.168.10.65 192.168.10.78 192.168.10.79
Problem 4:
IP address: 192.168.10.0 (given)
Minimum number of subnets needed: 31
a. Slash prefix: _________________________________________
b. Subnet Mask: _________________________________________
c. Bits Borrowed: _________________________________________
d. Number of possible subnets: _________________________________________
e. Magic number: _________________________________________
f. Number of valid hosts per subnet: _________________________________________
g. (Sub) network address of subnet 0: _________________________________________
h. First usable host address in subnet 0: _________________________________________
i. Last usable host address in subnet 0: _________________________________________
j. Broadcast address in subnet 0: _________________________________________
k. (Sub) Network address in subnet 1: _________________________________________
l. Last usable host address in subnet 2: _________________________________________
Subnet Subnet address 1st Host address Last Host address Broadcast
0
1
2
3
Etc.
Problem 5:
IP address: 192.10.10.0 (given) (Note that this address is slightly different than above)
Minimum number of hosts needed per subnet: 16
(Remember that the goal is to find a solution that will waste as few host addresses as possible but still satisfy the requirements.)
a. Slash prefix: _________________________________________
b. Subnet Mask: _________________________________________
c. Bits Borrowed: _________________________________________
d. Number of possible subnets: _________________________________________
e. Magic number: _________________________________________
f. Number of valid hosts per subnet: _________________________________________
g. (Sub) network address of subnet 0: _________________________________________
h. First usable host address in subnet 0: _________________________________________
i. Last usable host address in subnet 0: _________________________________________
j. Broadcast address in subnet 0: _________________________________________
k. (Sub) Network address in subnet 1: _________________________________________
l. Last usable host address in subnet 2: _________________________________________
Subnet Subnet address 1st Host address Last Host address Broadcast
0
1
2
3
Etc.
Answer the following questions. Try to answer them without using tables to guide you:
1. How many usable hosts per sub-network will you have using a /20 address? ______
2. Given a Class B address, what is the magic number if you need to subnet using a /23 prefix? ______________________
3. In a Class B address, how many sub-networks can you have with a /18 prefix? _______________
4. How many total addresses per network can you have with a subnet mask of 255.255.224.0? (Note that total addresses include network and broadcast addresses.)___________
[Solved] BMIS 330 LAB 18 | Complete Solution
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- Submitted On 20 Aug, 2015 12:53:08
- AceTutor
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