Cash-back offer from May 2nd to 7th, 2024: Get a flat 10% cash-back credited to your account for a minimum transaction of $50.Post Your Questions Today!

Question DetailsNormal
$ 50.00

Stat225Quiz 1 SolutionsA+++

Question posted by
Online Tutor Profile
request

(1) A is an event, and S is sample space. Then P A =
N(A)
N(S)
; P A = 1 − P(AC)
(2) A, B are events. P(A|B)=
P(A∩B)
P(B)
; A and B are independent if and only if P A ∩ B = P(A) ∙ P(B)
(3) P A ∪ B = P A + P B − P(A ∩ B) ; (A ∪ B)C = AC ∩ BC ; (A ∩ B)C = AC ∪ BC
Stat 225 - Quiz 1 Name________________________________________ 09/05/2012 You have 20 minutes to finish this quiz. A survey was conducted asking 200 randomly chosen Purdue students what sports they enjoyed among football, basketball and hockey. The results are summarized below. 20 students said they like none of the sports listed. 30 students said they like all of the sports listed. 55 students like both football and basketball. 65 students like both basketball and hockey. 110 students like basketball. 95 students like hockey. 100 students like football. 160 students like either football or hockey. The sample is representative of the student population at Purdue. Answer the following questions. If a decimal answer is not exact, please round to 2 non-zero decimal places.
1. Finish the below Venn diagram to describe the breakdown. (3 points)
Football Basketball Hockey
2. What is the probability that a randomly picked student at Purdue likes football or basketball? (2 points)
3. What is the probability that a randomly picked student at Purdue likes neither football nor hockey? (3 points)
(1) A is an event, and S is sample space. Then P A =
N(A)
N(S)
; P A = 1 − P(AC)
(2) A, B are events. P(A|B)=
P(A∩B)
P(B)
; A and B are independent if and only if P A ∩ B = P(A) ∙ P(B)
(3) P A ∪ B = P A + P B − P(A ∩ B) ; (A ∪ B)C = AC ∩ BC ; (A ∩ B)C = AC ∪ BC
Suppose in the 2012 season, the New York Jets will either start Mark Sanchez, Tim Tebow, or Greg McElroy as quarterback for each game. Assume that if the Jets start Mark Sanchez, they have 0.6 probability of winning the game. If they start Tim Tebow, they have 0.6 probability of losing the game. If they start Greg McElroy, their losing probability is 4 times as much as that for winning. The Jets coach will start Mark Sanchez with probability 0.7, and Tim Tebow with probability 0.2.
4. Draw a tree diagram to describe this situation. (3 points)
5. Given the Jets lose the game, what is the probability that they started Tim Tebow as quarterback? (3 points)
6. Knowing the Jets won the game, what is the chance they started Mark Sanchez or Tim Tebow in this game? (3 points)
7. Is starting Tim Tebow independent with winning the game? Justify the answer. (3 points)
(1) A is an event, and S is sample space. Then P A =
N(A)
N(S)
; P A = 1 − P(AC)
(2) A, B are events. P(A|B)=
P(A∩B)
P(B)
; A and B are independent if and only if P A ∩ B = P(A) ∙ P(B)
(3) P A ∪ B = P A + P B − P(A ∩ B) ; (A ∪ B)C = AC ∩ BC ; (A ∩ B)C = AC ∪ BC
Stat 225 - Quiz 1 Name________________________________________ 09/05/2012 You have 20 minutes to finish this quiz. A survey was conducted asking 200 randomly chosen Purdue students what sports they enjoyed among football, basketball and hockey. The results are summarized below. 30 students said they like none of the sports listed. 40 students said they like all of the sports listed. 75 students like both football and basketball. 55 students like both basketball and hockey. 110 students like basketball. 130 students like football. 85 students like hockey. 150 students like either football or hockey. The sample is representative of the student population at Purdue. Answer the following questions. If a decimal answer is not exact, please round to 2 non-zero decimal places.
1. Finish the below Venn diagram to describe the breakdown. (3 points)
2. What is the probability that a randomly picked student at Purdue likes football or basketball? (2 points)
3. What is the probability that a randomly picked student at Purdue likes neither football nor hockey? (3 points)
(1) A is an event, and S is sample space. Then P A =
N(A)
N(S)
; P A = 1 − P(AC)
(2) A, B are events. P(A|B)=
P(A∩B)
P(B)
; A and B are independent if and only if P A ∩ B = P(A) ∙ P(B)
(3) P A ∪ B = P A + P B − P(A ∩ B) ; (A ∪ B)C = AC ∩ BC ; (A ∩ B)C = AC ∪ BC
Suppose in the 2012 season, the New York Jets will either start Mark Sanchez, Tim Tebow, or Greg McElroy as quarterback for each game. Assume that if the Jets start Mark Sanchez, they have 0.55 probability of winning the game. If they start Tim Tebow, they have 0.55 probability of losing the game. If they start Greg McElroy, their losing probability is 3 times as much as that for winning. The Jets coach will start Mark Sanchez with probability 0.75, and Tim Tebow with probability 0.22.
4. Draw a tree diagram to describe this situation. (3 points)
5. Given the Jets lose the game, what is the probability that they started Tim Tebow as quarterback? (3 points)
6. Knowing the Jets won the game, what is the chance they started Mark Sanchez or Tim Tebow in this game? (3 points)
7. Is starting Tim Tebow independent with winning the game? Justify the answer. (3 points)
(1) A is an event, and S is sample space. Then P A =
N(A)
N(S)
; P A = 1 − P(AC)
(2) A, B are events. P(A|B)=
P(A∩B)
P(B)
; A and B are independent if and only if P A ∩ B = P(A) ∙ P(B)
(3) P A ∪ B = P A + P B − P(A ∩ B) ; (A ∪ B)C = AC ∩ BC ; (A ∩ B)C = AC ∪ BC
Stat 225 - Quiz 1 Name________________________________________ 09/05/2012 You have 20 minutes to finish this quiz. A survey was conducted asking 200 randomly chosen Purdue students what sports they enjoyed among football, basketball and hockey. The results are summarized below. 10 students said they like none of the sports listed. 50 students said they like all of the sports listed. 85 students like both football and basketball. 70 students like both basketball and hockey. 130 students like basketball. 120 students like football. 100 students like hockey. 165 students like either football or hockey. The sample is representative of the student population at Purdue. Answer the following questions. If a decimal answer is not exact, please round to 2 non-zero decimal places.
1. Finish the below Venn diagram to describe the breakdown. (3 points)
2. What is the probability that a randomly picked student at Purdue likes football or basketball? (2 points)
3. What is the probability that a randomly picked student at Purdue likes neither football nor hockey? (3 points)
(1) A is an event, and S is sample space. Then P A =
N(A)
N(S)
; P A = 1 − P(AC)
(2) A, B are events. P(A|B)=
P(A∩B)
P(B)
; A and B are independent if and only if P A ∩ B = P(A) ∙ P(B)
(3) P A ∪ B = P A + P B − P(A ∩ B) ; (A ∪ B)C = AC ∩ BC ; (A ∩ B)C = AC ∪ BC
Suppose in the 2012 season, the New York Jets will either start Mark Sanchez, Tim Tebow, or Greg McElroy as quarterback for each game. Assume that if the Jets start Mark Sanchez, they have 0.58 probability of winning the game. If they start Tim Tebow, they have 0.58 probability of losing the game. If they start Greg McElroy, their losing probability is 9 times as much as that for winning. The Jets coach will start Mark Sanchez with probability 0.65, and Tim Tebow with probability 0.25.
4. Draw a tree diagram to describe this situation. (3 points)
5. Given the Jets lose the game, what is the probability that they started Tim Tebow as quarterback? (3 points)
6. Knowing that Jets won the game, what is the chance that they started Mark Sanchez or Tim Tebow in this game? (3 points)
7. Is starting Tim Tebow independent with winning the game? Justify the answer. (3 points)
(1) A is an event, and S is sample space. Then P A =
N(A)
N(S)
; P A = 1 − P(AC)
(2) A, B are events. P(A|B)=
P(A∩B)
P(B)
; A and B are independent if and only if P A ∩ B = P(A) ∙ P(B)
(3) P A ∪ B = P A + P B − P(A ∩ B) ; (A ∪ B)C = AC ∩ BC ; (A ∩ B)C = AC ∪ BC
Stat 225 - Quiz 1 Name________________________________________
09/05/2012 You have 20 minutes to finish this quiz. A survey was conducted asking 200 randomly chosen Purdue students what sports they enjoyed among football, basketball and hockey. The results are summarized below. 15 students said they like none of the sports listed. 55 students said they like all of the sports listed. 85 students like both football and basketball. 80 students like both basketball and hockey. 130 students like basketball. 130 students like football. 115 students like hockey. 165 students like either football or hockey. The sample is representative of the student population at Purdue. Answer the following questions. If a decimal answer is not exact, please round to 2 non-zero decimal places.
1. Finish the below Venn diagram to describe the breakdown. (3 points)
2. What is the probability that a randomly picked student at Purdue likes football or basketball? (2 points)
3. What is the probability that a randomly picked student at Purdue likes neither football nor hockey? (3 points)
(1) A is an event, and S is sample space. Then P A =
N(A)
N(S)
; P A = 1 − P(AC)
(2) A, B are events. P(A|B)=
P(A∩B)
P(B)
; A and B are independent if and only if P A ∩ B = P(A) ∙ P(B)
(3) P A ∪ B = P A + P B − P(A ∩ B) ; (A ∪ B)C = AC ∩ BC ; (A ∩ B)C = AC ∪ BC
Suppose in the 2012 season, the New York Jets will either start Mark Sanchez, Tim Tebow, or Greg McElroy as quarterback for each game. Assume that if the Jets start Mark Sanchez, they have 0.53 probability of winning the game. If they start Tim Tebow, they have 0.53 probability of losing the game. If they start Greg McElroy, their losing probability is 4 times as much as that for winning. The Jets coach will start Mark Sanchez with probability 0.8, and Tim Tebow with probability 0.18.
4. Draw a tree diagram to describe this situation. (3 points)
5. Given the Jets lose the game, what is the probability that they started Tim Tebow as quarterback? (3 points)
6. Knowing that Jets won the game, what is the chance that they started Mark Sanchez or Tim Tebow in this game? (3 points)
7. Is starting Tim Tebow independent with winning the game? Justify the answer. (3 points)

Available Answer
Other Similar Questions
User Profile
NUMBE...

stat225Quiz 1 SolutionsA+++

(1) A is an event, and S is sample space. Then P A = N(A) N(S) ; P A = 1 − P(AC) (2) A, B are events. P(A|B)= P(A∩B) P(B) ; A and B are independent if and only if P A ∩ B = P(A) ∙ P(B) (3) P A ∪ B = P A + P B − P(...
User Profile
NUMBE...

stat225Quiz 3 SolutionsA++++

STAT 225 Quiz 3 Sarah is examining the concession stands before going to watch a movie. The probability that she buys candy is 0.70. If she buys candy, there is a 0.40 probability that she will also buy popcorn and soda, a 0...

The benefits of buying study notes from CourseMerits

homeworkhelptime
Assurance Of Timely Delivery
We value your patience, and to ensure you always receive your homework help within the promised time, our dedicated team of tutors begins their work as soon as the request arrives.
tutoring
Best Price In The Market
All the services that are available on our page cost only a nominal amount of money. In fact, the prices are lower than the industry standards. You can always expect value for money from us.
tutorsupport
Uninterrupted 24/7 Support
Our customer support wing remains online 24x7 to provide you seamless assistance. Also, when you post a query or a request here, you can expect an immediate response from our side.
closebutton

$ 629.35