STAT Mutiple Choice Question | Complete Solution
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P(Z > 0.74) |
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b. |
P(Z ≤ −1.92) |
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c. |
P(0 ≤ Z ≤ 1.62) |
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d. |
P(−0.90 ≤ Z ≤ 2.94) |
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a. |
P(X > 10) |
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b. |
P(X > 20) |
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c. |
P(10 < X < 20) |
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a. |
Find P(X ≤ 86). (Round "z" value to 2 decimal places and final answer to 4 decimal places.) |
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P(X ≤ 86) |
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b. |
Find P(80 ≤ X ≤ 100). (Round "z" value to 2 decimal places and final answer to 4 decimal places.) |
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P(80 ≤ X ≤ 100) |
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c. |
Find x such that P(X ≤ x) = 0.40. (Round "z" value to 2 decimal places and final answer to nearest whole number.) |
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x |
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d. |
Find x such that P(X > x) = 0.90. (Round "z" value to 2 decimal places and final answer to 1 decimal place.) |
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a. |
Find P(X > 7.6). (Round "z" value to 2 decimal places and final answer to 4 decimal places.) |
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P(X > 7.6) |
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b. |
Find P(7.4 ≤ X ≤ 10.6). (Round "z" value to 2 decimal places and final answer to 4 decimal places.) |
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P(7.4 ≤ X ≤ 10.6) |
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c. |
Find x such that P(X > x) = 0.025. (Round "z" value and final answer to 2 decimal places.) |
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x |
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Find x such that P(x ≤ X ≤ 2.5) = 0.4943. (Negative value should be indicated by a minus sign. Round "z" value and final answer to 2 decimal places.) |
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x |
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a. |
P(Z ≤ z) = 0.9744 |
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b. |
P(Z > z) = 0.8389 |
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c. |
P(−z ≤ Z ≤ z) = 0.95 |
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d. |
P(0 ≤ Z ≤ z) = 0.3315 |
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Exhibit 6-1. You are planning a May camping trip to Denali National Park in Alaska and want to make sure your sleeping bag is warm enough. The average low temperature in the park for May follows a normal distribution with a mean of 32°F and a standard deviation of 8°F.
Refer to Exhibit 6-1. One sleeping bag you are considering advertises that it is good for temperatures down to 25°F. What is the probability that this bag will be warm enough on a randomly selected May night at the park?
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0.8800 |
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0.8106 |
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0.1894 |
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0.3106 |
It is known that the length of a certain product X is normally distributed with μ = 20 inches. How is the probability 
related to 
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\ is the same as \. |
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\ is smaller than \. |
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No comparison can be made with the given information. |
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\ is greater than \. |
Let X be normally distributed with mean μ and standard deviation σ > 0. Which of the following is true about the z value corresponding to a given x value?
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A positive z = (x - μ)/σ indicates how many standard deviations x is above μ. |
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All of the above. |
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A negative z = (x - μ)/σ indicates how many standard deviations x is below μ. |
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The z value corresponding to x = μ is zero. |
Find the probability P(-1.96 ≤ Z ≤ 0).
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0.0250 |
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0.4750 |
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0.5250 |
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0.0500 |
The probability that a normal random variable is less than its mean is ___.
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1.0 |
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Cannot be determined |
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0.0 |
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0.5 |
How many parameters are needed to fully describe any normal distribution?
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2 |
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1 |
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3 |
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4 |
The time to complete the construction of a soapbox derby car is normally distributed with a mean of three hours and a standard deviation of one hour. Find the probability that it would take between 2.5 and 3.5 hours to construct a soapbox derby car.
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0.3085 |
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0.6170 |
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0.3830 |
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0.6915 |
Let X be normally distributed with mean µ = 250 and standard deviation σ = 80. Find the value x such that P(X ≤ x) = 0.9394.
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126 |
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1.55 |
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374 |
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-1.55 |
Exhibit 6-2. Gold miners in Alaska have found, on average, 12 ounces of gold per 1000 tons of dirt excavated with a standard deviation of 3 ounces. Assume the amount of gold found per 1000 tons of dirt is normally distributed.
Refer to Exhibit 6-2. What is the probability the miners find more than 16 ounces of gold in the next 1000 tons of dirt excavated?
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0.5918 |
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0.0918 |
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0.9082 |
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0.4082 |
Top of Form
If X has a normal distribution with and , then the probability can be expressed in terms of a standard normal variable Z as _______.
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[Solved] STAT Mutiple Choice Question | Complete Solution
- This solution is not purchased yet.
- Submitted On 11 Mar, 2015 01:31:37
- ExpertT
- Rating : 109
- Grade : A+
- Questions : 1
- Solutions : 1026
- Blog : 0
- Earned : $53187.54
Round "z" value to 2 de... 
STAT Mutiple Choice Question | Complete Solution
Round "z" value to 2 decimal places and final answer to 4 decimal places.)(Round "z" value to 2 decimal places and final answer to 1 decimal place.)
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