TEST BANK FOR Microelectronics Circuit Analysis and Design 4th Edition By Donald Neamen
- GradeMaster1
- Rating : 1
- Grade : C+
- Questions : 0
- Solutions : 1124
- Blog : 0
- Earned : $278.60
1.1
3/ 2 Eg / 2kT
in BT e− =
(a) Silicon
(i) ( )( ) ( )( )
[ ]
15 3/ 2
6
19
8 3
5.23 10 250 exp 1.1
2 86 10 250
2.067 10 exp 25.58
1.61 10 cm
i
i
n
n
−
−
⎡ − ⎤ = × ⎢ ⎥
⎢⎣ × ⎥⎦
= × −
= ×
(ii) ( )( ) ( )( )
[ ]
15 3/ 2
6
19
11 3
5.23 10 350 exp 1.1
2 86 10 350
3.425 10 exp 18.27
3.97 10 cm
i
i
n
n
−
−
⎡ − ⎤ = × ⎢ ⎥
⎢⎣ × ⎥⎦
= × −
= ×
(b) GaAs
(i) ( )( ) ( )( )
( ) [ ]
14 3/ 2
6
17
3 3
2.10 10 250 exp 1.4
2 86 10 250
8.301 10 exp 32.56
6.02 10 cm
i
i
n
n
−
−
⎡ − ⎤ = × ⎢ ⎥
⎢⎣ × ⎥⎦
= × −
= ×
(ii) ( )( ) ( )( )
( ) [ ]
14 3/ 2
6
18
8 3
2.10 10 350 exp 1.4
2 86 10 350
1.375 10 exp 23.26
1.09 10 cm
i
i
n
n
−
−
⎡ − ⎤ = × ⎢ ⎥
⎢⎣ × ⎥⎦
= × −
= ×
______________________________________________________________________________________
1.2
a. 3/ 2 exp
2 i
n BT Eg
kT
⎛ − ⎞ = ⎜ ⎟
⎝ ⎠
12 15 3 / 2
6
10 5.23 10 exp 1.1
2(86 10 )( )
T
− T
⎛ − ⎞
= × ⎜ ⎟ ⎝ × ⎠
3
1.91 10 4 T 3/ 2 exp 6.40 10
T
− ⎛ × ⎞
× = ⎜ − ⎟
⎝ ⎠
By trial and error, T ≈ 368 K
b. 109 cm 3 i n = −
( )( )
9 15 3/ 2
6
10 5.23 10 exp 1.1
2 86 10
T
− T
⎛ − ⎞ = × ⎜ ⎟
⎜ × ⎟ ⎝ ⎠
3
1.91 10 7 T3/ 2 exp 6.40 10
T
− ⎛ × ⎞
× = ⎜ − ⎟
⎝ ⎠
By trial and error, T ≈ 268° K
______________________________________________________________________________________
Microelectronics: Circuit Analysis and Design, 4th edition Chapter 1
By D. A. Neamen Problem Solutions
______________________________________________________________________________________
1.3
Silicon
(a) ( )( ) ( )( )
( ) [ ]
15 3/ 2
6
18
10 3
5.23 10 100 exp 1.1
2 86 10 100
5.23 10 exp 63.95
8.79 10 cm
i
i
n
n
−
− −
⎡ − ⎤ = × ⎢ ⎥
⎢⎣ × ⎥⎦
= × −
= ×
(b) ( )( ) ( )( )
( ) [ ]
15 3/ 2
6
19
10 3
5.23 10 300 exp 1.1
2 86 10 300
2.718 10 exp 21.32
1.5 10 cm
i
i
n
n
−
−
⎡ − ⎤ = × ⎢ ⎥
⎢⎣ × ⎥⎦
= × −
= ×
(c) ( )( ) ( )( )
( ) [ ]
15 3/ 2
6
19
14 3
5.23 10 500 exp 1.1
2 86 10 500
5.847 10 exp 12.79
1.63 10 cm
i
i
n
n
−
−
⎡ − ⎤ = × ⎢ ⎥
⎢⎣ × ⎥⎦
= × −
= ×
Germanium.
(a) ( )( ) ( )( ) 15 3/ 2 ( 18 ) [ ]
6
3
1.66 10 100 exp 0.66 1.66 10 exp 38.37
2 86 10 100
35.9 cm
i
i
n
n
−
−
⎡ − ⎤ = × ⎢ ⎥ = × −
⎢⎣ × ⎥⎦
=
(b) ( )( ) ( )( ) 15 3/ 2 ( 18 ) [ ]
6
13 3
1.66 10 300 exp 0.66 8.626 10 exp 12.79
2 86 10 300
2.40 10 cm
i
i
n
n
−
−
⎡ − ⎤ = × ⎢ ⎥ = × −
⎢⎣ × ⎥⎦
= ×
(c) ( )( ) ( )( ) 15 3/ 2 ( 19 ) [ ]
6
15 3
1.66 10 500 exp 0.66 1.856 10 exp 7.674
2 86 10 500
8.62 10 cm
i
i
n
n
−
−
⎡ − ⎤ = × ⎢ ⎥ = × −
⎢⎣ × ⎥⎦
= ×
______________________________________________________________________________________
1.4
(a) n-type; = 1015 cm ; no −3 ( ) 11
15
2 13 2
5.76 10
10
2.4 10 = ×
×
= =
o
i
o n
n
p cm−3
(b) n-type; = 1015 cm ; no −3 ( ) 5
15
2 10 2
2.25 10
10
1.5 10 = ×
×
= =
o
i
o n
n
p cm−3
______________________________________________________________________________________
Microelectronics: Circuit Analysis and Design, 4th edition Chapter 1
By D. A. Neamen Problem Solutions
______________________________________________________________________________________
1.5
(a) p-type; = 1016 cm ; po −3 ( ) 4
16
2 6 2
3.24 10
10
1.8 10 = × −
×
= =
o
i
o p
n
n cm−3
(b) p-type; = 1016 cm ; po −3 ( ) 10
16
2 13 2
5.76 10
10
2.4 10 = ×
×
= =
o
i
o p
n
n cm−3
______________________________________________________________________________________
1.6
(a) n-type
(b)
( )
16 3
10 2 2
3 3
16
5 10 cm
1.5 10
4.5 10 cm
5 10
o d
i
o
o
n N
p n
n
−
−
= = ×
×
= = = ×
×
(c) 5 1016 cm 3 o d n = N = × −
From Problem 1.1(a)(ii) 3.97 1011 cm 3 i n = × −
( )11 2
6 3
16
3.97 10
3.15 10 cm
5 10 o p − ×
= = ×
×
______________________________________________________________________________________
1.7
(a) p-type; = 5×1016 cm ; po −3 ( ) 3
16
2 10 2
4.5 10
5 10
1.5 10 = ×
×
×
= =
o
i
o p
n
n cm−3
(b) p-type; = 5×1016 cm ; po −3 ( ) 5
16
2 6 2
6.48 10
5 10
1.8 10 = × −
×
×
= =
o
i
o p
n
n cm−3
______________________________________________________________________________________
1.8
(a) Add boron atoms
(b) = = 2×1017 cm Na po −3
(c) ( ) 3
17
2 10 2
1.125 10
2 10
1.5 10 = ×
×
×
= =
o
i
o p
n
n cm−3
______________________________________________________________________________________
1.9
(a)
( )
15 3
10 2 2
4 3
15
5 10
1.5 10
4.5 10
5 10
o
i
o o
o
n cm
p n p
n
−
cm−
= ×
×
= = ⇒ = ×
×
(b) > ⇒n-type no po
(c) 5 1015 3 o d n ≅ N = × cm−
______________________________________________________________________________________
Microelectronics: Circuit Analysis and Design, 4th edition Chapter 1
By D. A. Neamen Problem Solutions
______________________________________________________________________________________
[Solved] TEST BANK FOR Microelectronics Circuit Analysis and Design 4th Edition By Donald Neamen
- This solution is not purchased yet.
- Submitted On 15 Nov, 2021 08:02:32
- GradeMaster1
- Rating : 1
- Grade : C+
- Questions : 0
- Solutions : 1124
- Blog : 0
- Earned : $278.60