TEST BANK FOR Introduction to Optics 3rd Ed By Frank L Pedrotti, Leno M Pedrotti, Leno S Pedrotti.
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1 -1 . a) =
h
p
=
h
m v
=
6. 63 1 0 3 4 J s
( 0. 05 kg) ( 20 m/ s)
= 6. 63 1 0 3 4 m
b) =
h
p
=
h
2 m E p =
6. 63 1 0 3 4 J s
[ ( 2 9. 1 1 1 0 3 1 kg) ( 1 0 1 . 602 1 0 1 9 J) ] 1 / 2 = 3. 88 1 0 1 0 m
1 -2. P =
Energy
time =
n h
t
=
n h c
t
=
1 00
6. 63 1 0 3 4 J s
3 1 08m/s
( 1 s) ( 550 1 0 9m)
= 3. 62 1 0 1 7 W
1 -3. The energy of a photon is given by E = h = h c/
At = 380 nm: E =
6. 63 1 0 3 4 J s
3 1 08m/s
380 1 0 9 m =
5. 23 1 0 1 9J
1 eV
1 . 60 1 0 1 9J = 3. 27 eV
At = 770 nm: E =
6. 63 1 0 3 4 J s
3 1 08m/s
770 1 0 9 m =
2. 58 1 0 1 9J
1 eV
1 . 60 1 0 1 9J = 1 . 61 eV
1 -4. p= E/ c = m c2/ c = m c = 2. 73 1 0 2 2 kg m/s, =
h
p
=
h c
E
=
h c
m c2 =
h
m c
= 2. 43 1 0 1 2 m
1 -5. Ev= 0 = m c2 =
9. 1 09 1 0 3 1 kg
2. 998 1 08 m/ s
2
=
8. 1 87 1 0 1 4 J
1 MeV
1 . 602 1 0 1 9 J = : 51 1 MeV
1 -6. c p= E2 p m2 c4; where E = EK + m c2 = ( 1 + 0. 51 1 ) )MeV: So c p= 1 . 51 1 2 0. 51 1 2 p MeV
That is, c p= 1 . 422 MeV and p= 1 . 422 MeV/ c.
1 -7. =
h c
E
=
6. 626 1 0 3 4 J s
2. 998 1 08 m/ s
E
1 eV
1 . 602 1 0 1 9 J
1 Å
1 0 1 0 m
=
1 2; 400
E
Å eV
1 -8. EK = m c2
1
1 v2/ c2
p 1
!
= m c2
h
1 v2/ c2
1 / 2
1
i
' m c2
1 ( 1 / 2) v2 / c2
1
=
1
2
m v2
1
[Solved] TEST BANK FOR Introduction to Optics 3rd Ed By Frank L Pedrotti, Leno M Pedrotti, Leno S Pedrotti.
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- Submitted On 15 Nov, 2021 02:37:21
- GradeMaster1
- Rating : 1
- Grade : C+
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- Solutions : 1124
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- Earned : $278.60