TEST BANK FOR Introduction to Mechatronics and Measurement Systems 4th Ed By David G.

2.1 D = 0.06408 in = 0.001628 m.
 = 1.7 x 10-8 m, L = 1000 m
2.2
(a) so
(b) so
(c) so
(d)
2.3 ,
a = 2 = red, b = 0 = black, c = 1 = brown, d = gold
2.4 In series, the trim pot will add an adjustable value ranging from 0 to its maximum value to
the original resistor value depending on the trim setting. When in parallel, the trim pot
could be 0 perhaps causing a short. Furthermore, the trim value will not be additive with
the fixed resistor.
2.5 When the last connection is made, a spark occurs at the point of connection as the
completed circuit is formed. This spark could ignite gases produced in the battery. The
negative terminal of the battery is connected to the frame of the car, which serves as a
ground reference throughout the vehicle.
A D2
4
= ---------- = 2.082  10–6
R L
A
= ------ = 8.2
R1 = 21  104  20% 168k  R1  252k
R2 = 07  103  20% 5.6k  R2  8.4k
Rs = R1 + R2 = 217k  20% 174k  Rs  260k
Rp
R1R2
R1 + R2
= -------------------
RpMIN
R1MINR2MIN
R1MIN R2MIN +
= ------------------------------- = 5.43k
RpMAX
R1MAXR2MAX
R1MAX R2MAX +
= ---------------------------------- = 8.14k
R1 = 10  102 R2 = 25  101
R
R1R2
R1 + R2
------------------- 10  102 25 10  1
10  102 + 25  101
= = --------------------------------------------------- = 20  101
Solutions Manual
4 Introduction to Mechatronics and Measurement Systems
2.6 No, as long as you are consistent in your application, you will obtain correct answers. If
you assume the wrong current direction, the result will be negative.
2.7 Place two 100 resistors in parallel and you immediately have a 50 resistance.
2.8 From KCL,
so from Ohm’s Law
Therefore, so
2.9 From Ohm’s Law and Question 2.8,
and for one resistor,
Therefore,
2.10
2.11
From KVL,
so
Therefore,
so or
Is = I1 + I2 + I3
Vs
Req
--------
Vs
R1
------
Vs
R2
------
Vs
R3
= + + ------
1
Req
-------- 1
R1
------ 1
R2
------ 1
R3
= + + ------ Req
R1R2R3
R2R3 + R1R3 + R1R2
= ----------------------------------------------------
V
Is
Req
--------
Is
R2R3 + R1R3 + R1R2
R1R2R3
----------------------------------------------------
= = ----------------------------------------------------
V = I1R1
I1
R2R3
R2R3 + R1R3 + R1R2
----------------------------------------------------
=   Is
R1R2
R1 + R2
-------------------
 
R1 
lim
R1R2
R1
= ------------ = R2
I Ceq
dV
dt
------- C1
dV1
dt
--------- C2
dV2
dt
= = = ---------
V = V1 + V2
dV
dt
-------
dV1
dt
---------
dV2
dt
= + ---------
I
Ceq
-------- I
C1
------ I
C2
= + ------ 1
Ceq
-------- 1
C1
------ 1
C2
= + ------ Ceq
C1C2
C1 + C2
= -------------------
Solutions Manual
Introduction to Mechatronics and Measurement Systems 5
2.12
and
From KCL,
Since
2.13
From KVL,
Since
2.14
From KCL, so
Therefore, so or
2.15 , regardless of the resistance value.
2.16 From Voltage Division,
V = V1 = V2
I1 C1
dV1
dt
--------- C1
dV
dt
= = ------- I2 C2
dV2
dt
--------- C2
dV
dt
= = -------
I I1 + I2 C1
dV
dt
------- C2
dV
dt
+ ------- dV
dt
= = = -------C1 + C2
I Ceq
dV
dt
= -------
Ceq = C1 + C2
I = I1 = I2
V V1 + V2 L1
dI
dt
----- L2
dI
dt
+ ----- dI
dt
= = = -----L1 + L2
V Leq
dI
dt
= -----
Leq = L1 + L2
V LdI
dt
----- L1
dI1
dt
------- L2
dI2
dt
= = = -------
I = I1 + I2 dI
dt
-----
dI1
dt
-------
dI2
dt
= + -------
VL
---- V
L1
----- V
L2
----- + = 1L--- 1
L1
----- 1
L2
= + ----- L
L1L2
L1 + L2
= ------------------
Vo = 1V
Vo
40
10 + 40
= ------------------5 – 15 = –8V
Solutions Manual
6